The answer is b -3.6 hope this helps and god bless my friend
Answer:
Step-by-step explanation:
function Fn = Fnorm(A)
[r,c] = size(A);
sum = 0;
for i=1:r
for j=1:c
sum = sum + (A(i,j) * A(i,j));
end
end
Fn = sqrt(sum);
end
A = [5 7 9; 1 8 4; 7 6 2]
fprintf("The Frobenius norm of an m × n matrix is\n");
Fn = Fnorm(A)
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It's B.
You can think of the action of multiplying matrix <em>A</em> onto any other matrix <em>X</em> as
• preserving the first row of <em>X</em> due to the +1 in the first column of the first row,
• negating the second row of <em>X</em> due to the -1 in the second column of the second row, and
• preserving the third row of <em>X</em> due to the +1 in the third column of the third row.
Steps to find the equation
1. Find the slope
2. Insert slope into the general equation
3. Find y-intercept
4. Insert -intercept into the equation found in step 2
And you get the equation of the line
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Find the slope
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2y - x = 4
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Rewrite into the form y = mx + c
----------------------------------------------------------------------------------------------
2y = x + 4
y = 1/2 x + 2
Slope = 1/2
Perpendicular slope = -2 (negative reciprocal)
----------------------------------------------------------------------------------------------
Insert slope into the equation
----------------------------------------------------------------------------------------------
y = mx + c
y = -2x + c
----------------------------------------------------------------------------------------------
Find y-intercept
----------------------------------------------------------------------------------------------
y = -2x + c
At point (1, 2)
2 = -2(1) + c
2 = -2 + c
c = 4
----------------------------------------------------------------------------------------------
Insert y-intercept into the equation y = -2x + c
----------------------------------------------------------------------------------------------
y = -2x + 4
----------------------------------------------------------------------------------------------
Answer: y = -2x + 4
----------------------------------------------------------------------------------------------
So since you know that x^2-1 is equal to (x-1)(x+1),
you can figure that this factors to
(y^2-x^3)(y^2+x^3)
because you know how the difference of two squares formula, stated on the top line of this answer.
