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3 years ago

Two similar prisms have heights 4 cm and 10 cm. What is the ratio of their surface areas?

Mathematics

2 answers:

TEA [102]3 years ago

6 0

4:25 is the correct answer

Alex73 [517]3 years ago

3 0

H 1 : H 2 = 4 : 10
H 1 = 2/5 H 2
and also for the base: L 1 = 2/5 L 2 and W 1 = 2/5 L 2
A 1 = 2 L 1 x W 1 + 2 L 1 x H 1 + 2 W 1 x H 1
A 2 = 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 x H 2
A 1 / A 2 = 4/25 *( 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 H 2 ) /
/ ( 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 x H 2 ) =
= 4/5
A 1 : A 2 = 4 : 25
Answer: B ) 4 : 25

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Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

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Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

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And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

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3 years ago

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Answer:

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Step-by-step explanation:

A method for calculating the area of a triangle when you know the lengths of all three sides.

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