Which is the correct graph of the inequality y >. 2x + 1

Solve for the value of z.<br> (52-6)<br> (22+5)

kogti [31]

Answer: 52-6=46 and 22+5=27 if you have to add the sums together then the final is 73 but if you subtract the sums then the final is 19

Step-by-step explanation:

7 0

3 years ago

What is the value of x? Enter your answer in the box.

mario62 [17]

X = 12

because if you notice, each of the angles have a little arc in the corner, which means they are congruent. if all three angles are congruent, that means each angle is 60° because each triangle has a maximum value of 180°. therefore, this means it is an equilateral triangle.

that being said, each side must be equal as well. so, you can use any two sides to find x by using each one on a different side of an equation, then isolating and solving.

5x - 22 = 3x + 2 = 4x - 10

so

5x - 22 = 3x + 2
3x + 2 = 4x - 10
4x - 10 = 5x - 22

whichever one you solve for, x = 12. and if you plug in that number for x, each side equals the same number = 38

8 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Which of the following points lies in the l and ll quadrants.

meriva

Answer:

Quadrant I: (1,1), (4,3)

Quadrant II: (-2, 3), (-1, 1)

Step-by-step explanation:

Quadrant I points have positive x and y values. Quandrant II points have negative x values and positive y values.

5 0

3 years ago

Aunt Maggie’s car broke down on iterestate 10. Sams towing charges a $57 hoop up fee and $2.00 per mile towed. Reginas towing ch

lawyer [7]

Answer:

Both situations can be modeled using linear functions

The rate of change of the function that models Regina's towing charge is 2.5

The y-intercept of the functions that model both situations represents the hook up fee

Step-by-step explanation:

Let

x -----> the number of miles towed

y ----> the total charge in dollars

we know that

The linear equation in slope intercept form is equal to

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value (value of y when the value of x is equal to zero)

we have

Sam’s Towing

In this case the slope of the linear equation is equal to the unit rate

The unit rate is $2.00 per mile towed

so

The y-intercept is equal to the charge per fee

so

therefore

the linear equation is

Regina’s Towing

In this case the slope of the linear equation is equal to the unit rate

The unit rate is $2.50 per mile towed

so

The y-intercept is equal to the charge per fee

so

therefore

the linear equation is

Verify each statement

case 1) Both situations can be modeled using linear functions

The statement is true

See the explanation

case 2) The y-intercept of the function that models Sam's Towing charges is 2

The statement is False

The y-intercept of the function that models Sam's Towing charges is $57

case 3) The rate of change of the function that models Regina's towing charge is 2.5

The statement is true

See the explanation

case 4) The y-intercept of the functions that model both situations represents the hook up fee

The statement is true

See the explanation

case 5) The rate of change of the functions that model both situations represent the miles traveled per hour

The statement is False

The rate of change of the functions that model both situations represent dollars by mile towed

8 0

3 years ago