Count how many plots are greater than 4, which in this case, is 8 children.
Answer:a is the correct option
Step-by-step explanation:
The table is divided into columns for month, sales and expense
Total number of sales for four months is determined by adding up the sales for each month. It becomes
35.75+65.34+12.15+49.68= $162.92
Total number of sales for four months is determined by adding up the expenses for each month. It becomes
43.18+52.24+41.09+59.50=196.01
Profit or loss = total sales - total expenses
Therefore 162.92-196.01 = - $33.09
It's a loss because it is negative
The <em>total</em> area of all six faces of the tunnel is
square centimeters.
<h2>Procedure - Surface area of a tunnel for a toy train</h2>
The surface area of the solid (
) used to represent the tunnel for a toy train is the sum of its six faces (two <em>semicircular</em> sections, inner <em>semicircular</em> arc section, outer <em>semicircular</em> arc section, two rectangles).
<h3>Determination of the surface area of the tunnel based on information of the diagram</h3>
We calculate the surface area as following:
![A = 2\cdot \frac{\pi}{2} \cdot [(10\,cm)^{2}-(8\,cm)^{2}] + \pi\cdot (8\,cm)\cdot (30\,cm) + \pi\cdot (10\,cm)\cdot (30\,cm) + 2\cdot (2\,cm)\cdot (30\,cm)](https://tex.z-dn.net/?f=A%20%3D%202%5Ccdot%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%5Ccdot%20%5B%2810%5C%2Ccm%29%5E%7B2%7D-%288%5C%2Ccm%29%5E%7B2%7D%5D%20%2B%20%5Cpi%5Ccdot%20%288%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29%20%2B%20%5Cpi%5Ccdot%20%2810%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29%20%2B%202%5Ccdot%20%282%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29)

The <em>total</em> area of all six faces of the tunnel is
square centimeters. 
To learn more on surface areas, we kindly invite to check this verified question: brainly.com/question/2835293
A/Wall if you have 20 and 30 that box is missing # so you will need to times and you will get something like this 20×30=60 and that's the missing #
B/Its going to be about 768 so you need to times and if you don't get 768
Complementary angles
Adjacent angles
Correct