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kramer
3 years ago
9

There are 5 animals in the field. Some are horses and some are ducks. There are 14 legs in all. How many of each animal are in t

he field?​
Mathematics
2 answers:
antiseptic1488 [7]3 years ago
5 0

Answer: 3 ducks 2 horses

Step-by-step explanation: ducks have 2 legs 3x2=6

horses have 4 legs 4x2=8

6+8=14

(Taking into account that none of the animals are amputees)

wariber [46]3 years ago
4 0

Answer:

2 horses and 3 ducks

Step-by-step explanation:

2 horses*4 legs=8 legs

3 ducks*2 legs=6 legs

Add both

8+6=14 legs

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Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC
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So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}
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Squaring both sides, we get
AC {}^{2} + BD {}^{2} + 2 AC.BD =50
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AC {}^{2} + BD {}^{2} = 50 - 16
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In △AOB, we have
OA {}^{2} + OB {}^{2} =AB {}^{2}
( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}
\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}
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34 = 4 AB {}^{2}

Square rooting both sides
\sqrt{34} = 2 AB
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Hope it helps!

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