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MariettaO [177]

3 years ago

9

using compound interest, how long does it take to double a 1000 dollar investment that pays 6.5% annual interest, compounded mon

thly?

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

11 years approx

Step-by-step explanation:

Given data

P=$1000

A=2000

R=6.5%

T= ?

Calculate time, solve for t

t = ln(A/P) / r

substitute

t=ln(2000/1000)/0.065

t=ln(2)/0.065

t=0.693/0.065

t=10.66

Hence the time is 11 years approx

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Determine the number of real solutions of -2x2 + 5x - 3 = 0.

andrew11 [14]

-2x^2 + 5x -3 =0

Find the discriminate:

In the given formula a = -2, b = 5 and c = -3

The discriminate is found using the formula b^2 - 4(ac)

Replace the letters with their values:

5^2 - 4(-2*-3)

25 - 4*6

25-24 = 1

When the discriminate is greater than or equal to 0, there are two real solutions.

The answer is c) 2

4 0

3 years ago

How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9

ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

$PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})$

Where:

$\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}$

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

$\frac{5.9}{100}=0.059$

Now we substitute the values:

$PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})$

Now we solve the operations, we get:

$PV_{\text{ord}}=39462.50$

Therefore, the present value must be $39462.50

8 0

1 year ago

Worth 10 points please help me ASAP

Nitella [24]

(2,-2) would be the answer I think

8 0

3 years ago

Sombody please help ASAP!

kotegsom [21]

Answer:

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Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

the question is in the picture below, if you could show all your work so i can see how to do it, that would be appreciated.

ki77a [65]

m∠R = 27.03°

Solution:

Given In ΔQRP, p = 28 km, q = 17 km, r = 15 km

To find the measure of angle R:

Law of cosine formula for ΔQRP:

$r^{2}=p^{2}+q^{2}-2 pq \cos R$

Substitute the given values in the above formula.

$(15)^{2}=(28)^{2}+(17)^{2}-2 (28)(17) \cos R$

$225=784+289-952 \cos R$

$225=1073-952 \cos R$

Switch the given equation.

$1073-952 \cos R=225$

Subtract 1073 from both side of the equation.

$-952 \cos R=-848$

Divide by –952 on both sides.

$$ \cos R=\frac{106}{119}$

$$ R=\cos^{-1} \left(\frac{106}{119}\right)$

$R=27.03^\circ$

Hence m∠R = 27.03°.

7 0

4 years ago