Answer:
like you wanna message on brainly? or...something else
Yes they are , since they are very common in ones body
Fixing two of the bits leaves four remaining positions, each with two possibilities (0 or 1), so there are

possible strings.
The remainder for 67 divided by 3 would be 1 because (this might be a bad explanation since i'm not good at explaining math without showing u my work) if u do divide 6 by 3, 3x2 is 6 and 6-6 is 0. Then if u divide 7 by 3, then 6 is the closest u can get to 7 without multiplying by a decimal. Then if u do 7-6, u get 1 and u cant divide 1 by 3 so the remainder would be 1.
12,800 is rounded to the nearest hundred