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baherus [9]
2 years ago
6

Please help .!!!!!!!!!!!!!!!

Mathematics
1 answer:
Yuliya22 [10]2 years ago
4 0

This being a piecewise function, trying to solve f(2), we must find which two equations we can use.

We can use the function '3x + 1' because its domain is 'x is greater than or equal to 2

   --> <u>f(2) = 3(2) + 1 = 7</u>

<u></u>

<u></u>

Hope that helps!

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How do I find the Q1 and Q3?<br><br> 0,0,1,2,2,3,4,4,4,4,5,6,6,7,7
Angelina_Jolie [31]

Answer:

Q1 = 2

Q3 = 6

Step-by-step explanation:

Mathematically, we have

Q1 = (n + 1)/4 th term

where n is the number of terms

By the count, we have n as 15

Q1 = (15 + 1)/4

Q1 = 4th term

Looking at the arrangement, the 4th term is 2

For Q3

Q3 = 3(n + 1)/4 th term

n = 15

Q3 = 3 * 4 = 12th term

The 12th term is 6

So that is the 3rd quartile

5 0
3 years ago
Toby is making a picture graph.Each picture of a book is equal to 2 books he has read. The row for Month 1 has 3 pictures of boo
xxTIMURxx [149]

Let

y-------> number of books read during the month 1

x------> number of picture of a book

we know that

y=2x

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for x=3\ pictures

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y=2*3=6\ books

therefore

the answer is

The number of books read during the month 1 is 6\ books


5 0
3 years ago
Read 2 more answers
PLEASE HELP DUE TODAYYYYY
Law Incorporation [45]
The answer to this is no solution because it is in simplest form. 

3x²-x+1 and 2x²+5x-4 can not be factored anymore. The expression given was in simplest form and could not be factored anymore. A trinomial expression is the form of ax²+bx+c. Factoring trinomials help you to put the equation in simplest form.

I hope this helps!!!!!


3 0
3 years ago
Read 2 more answers
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

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RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
Q16. Find x^2 + 1/x^2 , if x + 1/x = 3
erica [24]

Answer:

2 \times  x \times \frac{1}{x}  =  2 \\  {x}^{2}   +  {y }^{2}  + 2xy =  {(x + y)}^{2} \\ {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2 = {(x +  \frac{1}{x} })^{2}  =  {3}^{2}  = 9

8 0
3 years ago
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