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4 years ago

Simplify 5 to the second power

Mathematics

1 answer:

kirill115 [55]4 years ago

3 0

5 to the second power is 5*5 which would be 25 so then youre left with 25+20, giving you 45 as your answer

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PLease Help!

Verizon [17]

You need to work backwards
if it is no more than 9 units away from 8
thus x must be 8-9<x<8+9 solving -1<x<17
so the answer is 4.

8 0

3 years ago

Find the equation of the line through point (2,2) and parallel to y=x+4. Use a forward slash (i.e.”/“) for fractions (e.g. 1/2 f

aleksandr82 [10.1K]

Answer:

The equation of the line is, y = x

Step-by-step explanation:

The constraints of the required linear equation are;

The point through which the line passes = (2, 2)

The line to which the required line is parallel = y = x + 4

Two lines are parallel if they have the same slope, therefore, we have;

The slope of the line, y = x + 4 is m = 1

Therefore, the slope of the required line = 1

The equation of the required lime in point and slope form becomes;

y - 2 = 1 × (x - 2)

∴ y = x - 2 + 2 = x

The equation of the required line is therefore, y = x

5 0

3 years ago

Comment all that apply

max2010maxim [7]

MCEA=90
mBEF=135
CEF is straight
AEF is right

4 0

4 years ago

Evaluate 5x-\dfrac xy5x−

olga2289 [7]

Answer:

5x - (x/y) = 18 when x=4 and y=2

Step-by-step explanation:

5x - (x/y)

When x=4 and y=2

Substitute the value of x=4 and y=2 into the expression

5x - (x/y)

5(4) - (4/2)

Multiply 5 by 4 and divide 4 by 2

=20 - 2

Subtract 2 from 20

=18

5x - (x/y) = 18 when x=4 and y=2

7 0

3 years ago

A right cone has radius 9cm and slant height 12cm. The radius and slant height are both multiplied by 2/3. Which of the followin

Olegator [25]

Answer:

The surface area is multiplied by 4/9.

Step-by-step explanation:

Surface Area of a Cone

Being r the radius and l the slant height of a cone, then its surface area is

$SA=\pi r^2+\pi r l$

Now let's think both the radius and the slant height are multiplied by the same factor k, i.e.

r'=kr

l'=kl

The new surface area is

$SA'=\pi r'^2+\pi r' l'=\pi (kr)^2+\pi \cdot kr\cdot kl=k^2\pi r^2+k^2\pi rl$

$SA'=k^2(\pi r^2+\pi rl)=k^2\cdot SA$

The new surface area is the $k ^2$ times original SA. Since k=2/3, then

$SA'=4/9\ SA$

The surface area is multiplied by 4/9.

6 0

3 years ago