Answer:
<h2>The year is 2010.</h2>
Step-by-step explanation:
The population of wolves is given by P(t) = 80(0.98)t.
The study has began in the year of 2000 and will end in 2020.
The difference between 2000 and 2009 is 9 years and the difference between 2009 and 2020 is 11 years.
Hence, the maximum value of t is 11.
The domain is 
.
The population will be 80, that is P(t) = 80.
Hence, 0.98t = 1, or, t = 
≅1.
In (2009 + 1) = 2010, the population of wolves will be 80.
Hello
the answer to this is
650
becomes we subtract
88 from 738
738-88 and we get 650
so we get
650
hope this helps
The question is so dry, mechanical, and devoid of emotion
that it's terrifying.
There is no way to assign a number to "How many people were
dying per day", and I would prefer not even to think about it in
those terms.
-- The period of time from August 4, 1914 until November 11, 1918 is 1,560 days.
-- The "average", or better, the "unit rate" of 10 million events in 1,560 days
is the quotient
(10,000,000 events) / (1,560 days)
= 6,410.3 events per day
= 267.1 events per hour
= 4.45 events per minute.
Reciprocally, this is a unit rate of
13.48 seconds per event,
sustained continuously for 4.274 years !
When will we ever learn ! ?
Answer:
Option D.
Step-by-step explanation:
We need to find the solution to the system graphed below.
If a system of equation have 2 linear equation then the intersection point of both lines lines is the solution of the system of equations.
In the given graph two straight lines intersect each other at (-1,-1).
Point of intersection = (-1,-1)
So, by using the given graph we can conclude that the solution of given system of equations is (-1,-1).
Therefore, the correct option is D.
<span>When your income is more than your expenses, y</span>ou have surplus
