28 dimes to 32 dimes

Let f(x) = twenty-four over the quantity of 3 x minus two. Find f(-2

bija089 [108]

$f(x)=\frac{24}{3x-2}\\\\f(-2)=?\\
Subtitude\ x=-2\\
f(-2)=\frac{24}{3*(-2)-2}=\frac{24}{-6-2}=\frac{24}{-8}=-3\\\\
Solution\ is\ f(-2)=-3.$

4 0

3 years ago

Read 2 more answers

Please help i dont know how to do this

maxonik [38]

Hello once again!

When you see a question like this, you need to find the equation of the straight line.

The formular used is y = mx + c
Where
m = slope
c = constant

First find the slope, since it's a straight line, any 2 coordinates can be used.

$m = { \frac{y_1 - y_2}{x_1-x_2} } \\ m= { \frac{16 - (- 8)}{-2 - 2} } \\ m= { \frac{24}{-4} } \\ m = -6$

Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.

In this case i'm using the coordinate
(-2, 16)

y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4

∴ The equation of the line is y = -6x + 4

The next step is to simply substitude in the x = 8 to the equation to find y.

y = -6(8) + 4
y = -48 + 4
y = -44

7 0

3 years ago

Please help me with this!!!

Dafna1 [17]

Answer:

option C is correct answer ..

Step-by-step explanation:

angle A + angle B + angle C = 180° ( by angle sum property of triangle )

3x + 4x-19+ 3x -1 = 180

10x + -20 = 180

10x = 180 +20 = 200

x = 200/10 = 20 °

angle A = 3× 20 = 60 °

angle B = 4× 20 - 1 9 = 61 °

angle C = 3× 20 -1 = 59 °

angle B is greatest so side opposite to it will be greatest in length ....so length of AC is greatest ....

so option C is the correct answer of this question ...

plz mark my answer as brainlist plzzzz vote me also as I have done this question by taking a lot of time Hope it will be helpful for you ....

5 0

3 years ago

Im confused..I feel as if what I’m learning in class itself is not as difficult as the problems my teacher gives us to take home

RideAnS [48]

Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function

x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)

on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2

ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive

we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down

it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)

it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)

4 0

3 years ago

I need all the angles of all four please, I uploaded them in order of each question

adelina 88 [10]

Answer:

Blurry

Step-by-step explanation:

8 0

3 years ago