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Lady_Fox [76]
3 years ago
9

What is 3/8 renamed as a decimal

Mathematics
1 answer:
QveST [7]3 years ago
7 0
The correct answer is <span>0.375

</span>
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Solve by writing and solving a matrix equation. Show all your work.
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3 years ago
two coins and one six sided number cube are tossed together. What is the probability of getting two heads and a four?
Elis [28]

Answer:

The probability of getting two heads and a four is 1/24

Step-by-step explanation:

The probability of getting a head upon a single toss of a coin, assuming the coin is fair is 1/2.

The probability of getting two heads upon tossing two coins together will simply be the product of the individual probabilities;

P (HH) = 1/2 * 1/2 = 1/4

On the other hand, the probability of getting a four upon rolling a six sided number cube is;

1/6

This is because the number 4 occurs only once in a total possible of 6 numbers.

Therefore, the probability of getting two heads and a four;

P (HH4) = 1/2 * 1/2 * 1/6 = 1/24 since the three events are independent.

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3 years ago
Recall from Example 1 that whenever Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing th
hammer [34]

Answer:

Required Probability in the lowest terms as fractions =  \frac{15}{182} =0.0824

Step-by-step explanation:

Step 1:-

Given Suzan has three red marbles, two green ones, five white ones, and two purple ones.

Total marbles = 3R+2G+5W+2P = 12

The number of exhaustive cases that the five marbles drawn from 12 marbles

n(S) = 12C_{5} = 792 ways

by using formula n_{Cr_{} } = \frac{n!}{(n-r)!r!} = \frac{12!}{(12-5)!5!}   = 792

The number of favorable cases

She has drawn two red marbles from 3 red marbles, that is 3c₂ ways

she has drawn one  marble drawn from 2 green marbles, that is 2c₁ ways

she has drawn one  marble drawn from 5 white marbles, that is 5c₁ ways

she has drawn one  marble drawn from 2 purple marbles, that is 2c₁ ways

The favorable cases are (n(E) = 3c₂ X 2c₁X5c₁X2c₁ = 60 ways

Required Probability = \frac{n(E)}{n(S)}

Required  probability = \frac{n(E)}{n(S)} = \frac{60}{792}

Required Probability in the lowest terms as fractions =  \frac{15}{182} =0.0824

3 0
3 years ago
5. Find the product<br> - 2x² (3x² - 4x+7)
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Student A B C D E F G H I J K L M N O
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Good evening ,

______

Answer:

Bar chart (graph)

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Step-by-step explanation:

Look at the photo below for the details,

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4 years ago
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