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3 years ago

Which is a secant of circle A?

Mathematics

2 answers:

qaws [65]3 years ago

8 0

Answer:

The correct option is line CD

Step-by-step explanation:

Given the diagram we have to find the secant of circle A.

Secant of a circle is a line intersecting the circle at exactly two different points and a chord is the line determined by these two.

In the circle A the only line intersect two different points is CD and the interval on a secant is the chord of circle.

Here, HG is only the chord of circle not secant.

Hence, the correct option is line CD

Dmitrij [34]3 years ago

7 0

A line passing through two points on a circle is called a secant. Therefore, the correct answer from the choices listed above is the last option. Line CD is the secant of circle A. It is clear that it is a line that passes through two points in the circle. Hope this answers the question.

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Aloiza [94]

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2 years ago

A fish tank contains 3 of water and is one-fourth full. How many quarts of water does the fish tank hold all together?

DIA [1.3K]

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2 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
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6 0

3 years ago

Help ASAP due in 6 mins

vova2212 [387]

Answer:

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Step-by-step explanation:

7 0

3 years ago

A freight train leaves a station and travels north at 60 mph. 4 hours later, a passenger train leaves on a parallel track and t

harkovskaia [24]

Answer:

first do:

60mph * 4 hours= 240mi

Let D = the distance the passenger train has to

travel to catch the freight train

Start a stopwatch when the passenger train leaves

Let t = the time on the stopwatch when they meet

Equation for freight train:

d-240=60t

Equation for passenger train:

d=100t

all together:

100t-240=60t

we can do 100t-60t because they both have (t)= 40t

40t=240 *now divide 240 by 40= 6

THEN do:

D= 100mph x 6= 600mi

They will meet 600 mi from the station

to check:

d-240=60t x 6

600-240= 360

60 x 6= 360

360=360

5 0

3 years ago