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3 years ago

Help plz neeed halp so much confusion

Mathematics

1 answer:

BartSMP [9]3 years ago

6 0

Solve the rational equation by combining expressions and isolating the variable m.

m = -10

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How to divide fractions

Tanzania [10]

Answer:

Step-by-step explanation:

When dividing fractions, I use a method called Keep Change Flip. Let's use the example 1/2 divided by 3/4 as an example. First, you have to keep the first fraction the same. This is what you currently have: 1/2 / 3/4. Next, you have to change the divison sign into a multiplication symbol. Now, this is what it should look like: 1/2 x 3/4. Then, you have to flip the fraction 3/4 into 4/3. Now, you have 1/2 x 4/3. Multiply the fraction. If you don't know how to, multiply numerator by numerator, denominator by denominator. You should get 4/6. However, this isn't your final answer. You can simplify this by dividing by 2 to get 2/3. So, your answer is 2/3. Hope this helped you and let me know if you need more help! :D

8 0

3 years ago

Factor the expression using the GFC 8 - 22a

Assoli18 [71]

8-22a

2(4-11a)

Take the largest number you can factor out of 8&22

3 0

3 years ago

Can someone answer this for me please

Nana76 [90]

Answer:

Step-by-step explanation:

6 0

3 years ago

10. In a survey of 212 people at the local track and field championship, 72% favored the home team

igomit [66]

Answer:

a. The margin of error for the survey is of 0.0308 = 3.08%.

b. The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error of the survey is:

$M = \sqrt{\frac{\pi(1-\pi)}{n}}$

The confidence interval can be written as:

$\pi \pm zM$

In a survey of 212 people at the local track and field championship, 72% favored the home team winning.

This means that $n = 212, \pi = 0.72$

a. Find the margin of error for the survey.

$M = \sqrt{\frac{0.72*0.28}{212}} = 0.0308$

The margin of error for the survey is of 0.0308 = 3.08%.

b. Give the 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Lower bound:

$\pi - zM = 0.72 - 1.96*0.0308 = 0.6596$

Upper bound:

$\pi + zM = 0.72 + 1.96*0.0308 = 0.7804$

As percent:

0.6596*100% = 65.96%

0.7804*100% = 78.04%.

The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

7 0

3 years ago

How do you find the intersection points given 2 or more equations in a ti-84 calculator?

mel-nik [20]

You click on the button that says "Y=" then you type in the equations into y=1 , y=2 and so forth. click graph and the lines will appear. use the up, down, left, and right buttons to move the cursor and find the exact point.

7 0

3 years ago