The equation 2 has a graph which is a straight line.
Why?
We can know which of the given equations has a graph which is a straight line just checking the exponents of the variables.
We must remember that every variable that has an exponent equal or higher than 2 (quadratic) will not have a straight line as a graphic.
So, checking the exponents from the given equations, we have:
Hence, we can see that the only equation that has a linear term (straight line graph), is the second equation.
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Note: I have attached a image for better understanding.
Answer:
m = - 1/4
Step-by-step explanation:
When two line is perpendicular to each other the product of them is - 1
So let the other line be B
Gradient of B = t
Gradient of A = 4
therefore m = - 1/4
Answer:
1232
Step-by-step explanation:
Answer:
First one
Step-by-step explanation:
If you simplify the first answer, the numbers in the answer will not repeat
<span>A)2x^2+3 is a transformation of f(x)=x^2: Stretch the graph vertically by a factor of 2 and then shift the entire resulting graph up by 3 units. The graph will still look like a parabola that opens up.
</span>B)-2x^2-3 is a transformation of f(x)=x^2: Stretch the graph vertically by a factor of 2, reflect the resulting graph in the x-axis, and then shift the entire resulting graph down by 3 units. The graph will still look like a parabola that opens down.
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Answers to C and D are very similar, except that we compress the graph of x^2 v ertically by a factor of (1/2).
None of these A, B, C, D is wrong.
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