Answer:
c. supplementary angles
Step-by-step explanation:
Answer:
The probability that a container will be shipped even though it contains 2 defectives if the sample size is 88, will be 
Step-by-step explanation:
The first step is to count the number of total possible random sets of taking a sample size of 88 engines over 1212 engines of the population, so ![\left[\begin{array}{ccc}1212\\88\end{array}\right] =1212C88=4.7205x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1212%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.7205x10%5E%7B135%7D)
The second step is to count the number of total possible random sets of taking a sample size of 88 engines over 1210 engines (discounting the 2 defective engines) as the possible ways to succeed, so ![\left[\begin{array}{ccc}1210\\88\end{array}\right] =1212C88=4.0596x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1210%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.0596x10%5E%7B135%7D)
Finally we need to compute 
, therefore the probability that a container will be shipped is
Answer:
x > -21/4
Step-by-step explanation:
<h2>66.66%</h2>
Step-by-step explanation:
<h3>game cost = $12 with 0% discount</h3><h3 /><h3>so, on putting x% discount videogame cost become $8</h3><h3><em>x</em><em>%</em><em> </em><em>d</em><em>i</em><em>s</em><em>c</em><em>o</em><em>u</em><em>n</em><em>t</em><em> </em><em>=</em><em> </em><em>x</em><em>/</em><em> </em><em>1</em><em>0</em><em>0</em><em> </em><em>×</em><em> </em><em>$</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>$</em><em>8</em></h3><h3><em>x</em><em>%</em><em> </em><em>d</em><em>i</em><em>s</em><em>c</em><em>o</em><em>u</em><em>n</em><em>t</em><em> </em><em>=</em><em> </em><em>6</em><em>6</em><em>.</em><em>6</em><em>6</em><em>%</em></h3>
<h2>
MARK ME AS BRAINLIST</h2>
(17 1/3) / 24 = x/1
cross multiply
24x = 52/3
x = 52/3 * 1/24
x = 52/72 = 13/18 inches per hr
