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Mumz [18]
3 years ago
5

Choose the correct graph to fit the inequality y<16x ^2

Mathematics
1 answer:
Luda [366]3 years ago
8 0

Answer:

The solution in the attached figure

Step-by-step explanation:

we have

y

we know that

The solution of the inequality is the shaded area below the dashed line of the parabola

The equation of the dashed line is the vertical parabola y=16x^{2}

therefore

The solution in the attached figure

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Factor Completely: x^2-13x-48
salantis [7]

Answer:

Therefore,the required factors are ( x - 16 ) and ( x + 3 )is

Step-by-step explanation:

Given:

x^{2} -13x-48

To Factorize:

Solution:

First remove the factor of -48 such that you multiply the two number, the Product should be -48 and the SUM should be -13.

-48 = -16 × 3

Here, -16 and 3 are the two  required numbers

now the given expression we will split the middle term  and Factorize the given equation.

x^{2} -13x-48 =x^{2} -16x+3x-48\\\\\\\textrm{removing x common and 3 common we get}\\x^{2} -13x-48=x(x-16)+3(x-16)\\\\x^{2} -13x-48=(x-16)(x-3)

Therefore,the required factors are ( x - 16 ) and ( x + 3 )

4 0
3 years ago
What transformation is represented by the rule (x, y)→(−x, −y) ?
postnew [5]
<span>rotation of 180° about the origin is correct. Changing the signs of both x and y rotates 180 degrees.
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5 0
3 years ago
Read 2 more answers
Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch
barxatty [35]

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = \frac{30-Q}{4}

The current price of the necklace $10.

Revenue function is given by R = P × Q = \frac{1}{4} × ( 30Q - Q^{2})

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

\frac{dR}{dQ} =  \frac{1}{4} × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

6 0
3 years ago
F(x) 5x/x-2
Phoenix [80]

Answer:

Vertical asymptote: x=2

Horizontal asymptote: y=5

Step-by-step explanation:

Hi there!

The parent function for a rational function has a horizontal asymptote at y=0 and a vertical asymptote at x=0.

First, we want to perform long division on 5x/x-2. Please check the image attached.

The result is 5+\displaystyle\frac{10}{x-2}.

Here are the transformations of a rational function:

f(x)=\displaystyle\frac{a}{b(x-h)}+k

a = vertical stretch

b = horizontal stretch

h = horizontal translation

k = vertical translation

Stretches don't change the location of the asymptotes, only the translations do.

According to 5+\displaystyle\frac{10}{x-2}, we applied a horizontal translation of 2 units right and a vertical translation of 5 units up. Therefore, our asymptotes are now x=2 and y=5.

I hope this helps!

6 0
2 years ago
Here is 19 and 20 thank yall
Veseljchak [2.6K]

Answer:

19: The difference between the temperature in Fair Banks and Barlow is 3°F

20: -13°F, -10°F, 15°F, 24°F.

Step-by-step explanation:

I'm assuming that by "compare", it means to find the difference between temperatures in question 19. If it means something else, let me know and I'll try and help you find it.

4 0
3 years ago
Read 2 more answers
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