The maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.
<h3>What is the range?</h3>
The range is the difference between the maximum and minimum.
Given to us
The standard diameter of a golf ball is 42.67 mm.
The discrepancy in diameter is more than 0.002 mm.
As it is given to us that the standard diameter of the golf ball is 42.67 mm while the discrepancy in diameter is more than 0.002 mm.
Maximum acceptable diameter = 42.67 mm + 0.002 mm = 42.672 mm
Minimum acceptable diameter = 42.67 mm - 0.002 mm = 42.668 mm
Hence, the maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.
Learn more about Range:
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Answer:
5 pack notebook
Step-by-step explanation:
5 pack notebook costs more because the 4 pack notebook costs 4 dollars w/ 2 cents off, and 5 pack notebook costs 5 dollars and with 1 cent of, so if ir increase by 1 dollar, than probably the 5 pack costs more. It is not about how many, but how much dollars are for per/ notebook.
Answer:
d
Step-by-step explanation:
I took the test. Hope I could help!
Answer:
73
Step-by-step explanation:
Answering:
188
Explaining:
To solve this problem, we must divide the total amount of money raised by the cost of the stuffed animals. Each stuffed animal costs $17. The club raised $3,207 to buy said stuffed animals. By dividing the money earned, which is also the money the club is able to spend, by the cost of a single/one stuffed animal, we will get how many stuffed animals the club can purchase with the money they currently possess. Our equation will look like this: 3,207 ÷ 17.
After dividing 3,207 by 17, we have the number 188.64705882. This can be rounded to the nearest tenth to create the simpler yet still accurate number 188.6.
Our final step is to round 188.6 down to the whole number it already has. (That is to say, simply cut off the fraction and remove it to get our answer.) This step must be done because we are buying stuffed animals in a real-world situation. The club would not be able to purchase part of a stuffed animal for a fraction of the cost, and the cost of the stuffed animals in the problem is a fixed value. This means that the fraction is irrelevant since we cannot purchase anything with it, effectively making it totally irrelevant to the answer. After removing the fraction from 188.6, we are left with 188.
Therefore, the maximum number of stuffed animals the club can buy is <em>188 stuffed animals</em>.
