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Greeley [361]
3 years ago
7

Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch

arge in order to maximize revenues?
Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = \frac{30-Q}{4}

The current price of the necklace $10.

Revenue function is given by R = P × Q = \frac{1}{4} × ( 30Q - Q^{2})

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

\frac{dR}{dQ} =  \frac{1}{4} × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

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STEP-BY-STEP EXPLANATION:

Given:

Standard deviation (σ) = 700

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\begin{gathered} \alpha=100\%-95\%=5\%=0.05 \\  \\ \alpha\text{/2}=\frac{0.05}{2}=0.025 \\  \\ \text{ The corresponding Z value for \alpha/2 = 0.025 is as follows:} \\  \\ Z_{\alpha\text{/2}}=1.96 \end{gathered}

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\begin{gathered} n=\left(\frac{Z_{\alpha\text{/2}}\cdot\sigma}{E}\right)^2 \\  \\ \text{ We replacing:} \\  \\ \:n=\left(\frac{1.96\cdot 700}{135}\right)^2 \\  \\ \:n=103.2858\cong104 \end{gathered}

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