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Greeley [361]
3 years ago
7

Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch

arge in order to maximize revenues?
Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = \frac{30-Q}{4}

The current price of the necklace $10.

Revenue function is given by R = P × Q = \frac{1}{4} × ( 30Q - Q^{2})

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

\frac{dR}{dQ} =  \frac{1}{4} × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

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Find the fifth roots of 243(cos 240° + i sin 240°).
Mazyrski [523]

Answer:

See below.

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos  Ф  + i sin  Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336).. (Answer).

7 0
3 years ago
Ten percent of 140,000 = ?​
Ostrovityanka [42]

Answer:

14000

Step-by-step explanation:

Of means multiply

10% * 140000

Change to decimal form

.10 * 140000

14000

4 0
3 years ago
Read 2 more answers
The graph of the function f(x) = -(x+6)(x + 2) is shown
Leokris [45]

Answer:

The function is increasing for all real values of x where

x < –4.

Step-by-step explanation:

we have

f(x)=-(x+6)(x+2)

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex (h,k) represent  a maximum

The roots of the function (or x-intercepts) are x=-6 and x=-2

The x-coordinate of the vertex is the midpoint of the roots

so

h=(-2-6)/2=-4

The y-coordinate of the vertex is

substitute the x-coordinate of the vertex in the quadratic equation

k=-(-4+6)(-4+2)

k=-(2)(-2)

k=4

The vertex is the point (-4,4)

The function is increasing in the interval (-∞,-4)

The function is decreasing in the interval (-4,∞)

6 0
3 years ago
Read 2 more answers
Can three segments with length 4 cm, 6 cm, and 11 cm be assembled to form an acute triangle, a right triangle, or an obtuse tria
Aliun [14]

Answer:

No

Step-by-step explanation:

Three segments 4cm, 6cm, and 11cm cannot form a right triangle because if they could, then by Pythagorean theorem, 4^2 + 6^2 = 11^2, which is not true.

Moreover, the three segments cannot form an acute or obtuse triangle because by Triangle Inequality Theorem, the sum of two sides has to be greater than the third side. Here, (4cm + 6cm) is NOT larger than 11cm, and thus you cannot form a triangle.

4 0
3 years ago
9) Five less than the square root of a number r
NNADVOKAT [17]
What’s number R? I need to know the number in order to find the square root of it. (:
8 0
2 years ago
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