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Greeley [361]
2 years ago
7

Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch

arge in order to maximize revenues?
Mathematics
1 answer:
barxatty [35]2 years ago
6 0

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = \frac{30-Q}{4}

The current price of the necklace $10.

Revenue function is given by R = P × Q = \frac{1}{4} × ( 30Q - Q^{2})

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

\frac{dR}{dQ} =  \frac{1}{4} × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

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tiny-mole [99]

Answer:

x=\frac{\sqrt{14} }{2}

Step-by-step explanation:

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We use just the positive root, since we are looking for an actual length. then, the requested side is:

x=\frac{\sqrt{14} }{2}

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2 years ago
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Answer:

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a=3.14

ok then the area of the sqare including the circle is 16 so

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1 year ago
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Sveta_85 [38]

Answer:

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Step-by-step explanation:

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