Question

Factor Completely: x^2-13x-48

Answer 1

Answer:

Therefore,the required factors are ( x - 16 ) and ( x + 3 )is

Step-by-step explanation:

Given:

$x^{2} -13x-48$

To Factorize:

Solution:

First remove the factor of -48 such that you multiply the two number, the Product should be -48 and the SUM should be -13.

-48 = -16 × 3

Here, -16 and 3 are the two  required numbers

now the given expression we will split the middle term  and Factorize the given equation.

$x^{2} -13x-48 =x^{2} -16x+3x-48\\\\\\\textrm{removing x common and 3 common we get}\\x^{2} -13x-48=x(x-16)+3(x-16)\\\\x^{2} -13x-48=(x-16)(x-3)$

Therefore,the required factors are ( x - 16 ) and ( x + 3 )