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3 years ago

Factor Completely: x^2-13x-48

Mathematics

1 answer:

salantis [7]3 years ago

4 0

Answer:

Therefore,the required factors are ( x - 16 ) and ( x + 3 )is

Step-by-step explanation:

Given:

$x^{2} -13x-48$

To Factorize:

Solution:

First remove the factor of -48 such that you multiply the two number, the Product should be -48 and the SUM should be -13.

-48 = -16 × 3

Here, -16 and 3 are the two required numbers

now the given expression we will split the middle term and Factorize the given equation.

$x^{2} -13x-48 =x^{2} -16x+3x-48\\\\\\\textrm{removing x common and 3 common we get}\\x^{2} -13x-48=x(x-16)+3(x-16)\\\\x^{2} -13x-48=(x-16)(x-3)$

Therefore,the required factors are ( x - 16 ) and ( x + 3 )

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Work out the co ordinates of the midpoint of (-2,-1) and (-2,4)

s2008m [1.1K]

Answer:

$(-2,\frac{3}{2})$

Step-by-step explanation:

To find the midpoint, simply use the Midpoint Formula.

The Midpoint Formula states that for two points $(x_1,y_1)$ and $(x_2,y_2)$ , the midpoint will be: $(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$ .

So, here, $(x_1,y_1)$ = (-2, -1) and $(x_2,y_2)$ = (-2, 4). The midpoint is then: $(\frac{-2+(-2)}{2} ,\frac{-1+4}{2} )=(\frac{-4}{2} ,\frac{3}{2} )=(-2,\frac{3}{2})$

Thus, the answer is $(-2,\frac{3}{2})$ .

Hope this helps!

4 0

3 years ago

Read 2 more answers

Mr. Saunders along with his wife and two children checked in for a 6 day stay at Disney world hotel. If he was charged $882 per

ddd [48]

$882/6 days = $147 per day

6 0

4 years ago

Suppose

Marrrta [24]

F(3) = t4(3) = 2

The value of the function at the point of expansion is the first (constant) term of the Taylor series.

6 0

4 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

10th term: a1 = 320,r=0.5

Strike441 [17]

Answer:

$a_{10}$ = $\frac{5}{8}$

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = $a_{1}$ $r^{n-1}$

Substitute in values

$a_{10}$ = 320 × $(\frac{1}{2}) ^{9}$

= 320 × $\frac{1}{512}$ = $\frac{320}{512}$ = $\frac{5}{8}$ = 0.625

4 0

3 years ago