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k0ka [10]
2 years ago
7

Fred randomly draws two cards from a standard deck of 52 cards. He does not replace the first card. What is the probability that

both cards are jacks?
 A. 1/221
B. 1/26
C. 1/1326
D. 1/663
Mathematics
2 answers:
Ludmilka [50]2 years ago
8 0
\\|\Omega|={52\choose2}=\frac{52!}{2!*50!}=51*26=1326
\\
\\|A|={4\choose2}=3*2=6
\\
\\P(A)=\frac{6}{1326}=\frac{1}{221}
\\
\\A.

arlik [135]2 years ago
5 0

1/221 ~~~~~~~~~~~~~~ APEX

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Click on the solution set below until the correct one is displayed.
Snowcat [4.5K]

Answer: Second Option

(Point in Quadrant I)

Step-by-step explanation:

The solution to a system of linear equations is the point where the two lines intersect.

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A number picked at random from the numbers 1 through 15 is prime. This "question" is on my study guide for Unit 6 Probability an
Sphinxa [80]

Solution:

we are given that

A number picked at random from the numbers 1 through 15 is prime.

As we know the number between 1 and 15 which are primes are listed below

2,3,5,7,11,13.

Here total number of favourable outcomes are 6.

The numbers 1 through 15 are as below:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15.

Here total number of possible outcoes are 15.

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime=\frac{6}{15}=\frac{2}{5}=0.40

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime is 0.4

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