N^2 + n - 120 = 0
Quadratic formula
a = 1, b = 1, c = -120
n = [-1 plus or minus root(1^2 - 4(1)(-120))] / 2(1)
n = (-1 plus or minus root481)/2
n =(approximately) 10.5 or -11.5
Answer:
The function of g(x) = 5x + 2
Step-by-step explanation:
Let us use the composite function to solve the question
∵ f(x) = 2x - 1
∵ f(g(x)) = 10x + 3
→ f(g(x)) means substitute x in f(x) by g(x)
∴ f(g(x)) = 2[g(x)] - 1
→ Equate the two right sides of f(g(x))
∴ 2[g(x)] - 1 = 10x + 3
→ Add 1 to both sides
∴ 2[g(x)] - 1 + 1 = 10x + 3 + 1
∴ 2[g(x)] = 10x + 4
→ Divide each term into both sides by 2
∵
=
+ 
∴ g(x) = 5x + 2
∴ The function of g(x) = 5x + 2
8^2, 4^3, and 2^6 are 3 ways
I think 20 hope that helps
Answer:
(4,3)
Step-by-step explanation:
To find the midpoint add the end points and divide by 2
P(2,5) S ( sx, sy) and the midpoint is and H (3,4)
X coordinate
( 2+ sx) /2 = 3
Multiply each side by 2
2+sx = 3*2
2+sx = 6
Subtract 2
sx = 4
Y coordinate
( 5+ sy) /2 = 4
Multiply each side by 2
5+sy = 4*2
5+sy = 8
Subtract 5
sy = 3
The end point is
(4,3)