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Kobotan [32]
3 years ago
12

Is it possible for a 5 digit number to be rounded to a 6 digit number

Mathematics
2 answers:
Alexandra [31]3 years ago
6 0
No because no matter what you round it to you will always be multiplying the 5 digit number by itself that many times
IrinaK [193]3 years ago
5 0
When we round a number the new rounded <span>number is </span>simpler but the value is kept close to what it was. The common method for rounding numbers is the following: we d<span><span>ecide which is the last digit to keep and l</span><span>eave this digit the same the same if the next digit is less than 5 or increase it by 1 if the next digit is bigger than 5.
</span></span>Because the next digit matter, it is not possible for a 5 digit number to be rounded to 6 digit number. 
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The sum of two polynomials is 8d^5-3c^3d^2+5c^2d^3-4CD^4+9. If one added is 2d^5-c^3d^4+8CD^4+1, what is the other added
insens350 [35]

Answer:

6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8

Step-by-step explanation:

We need to subtract the given polynomial from the sum:-

8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^4 + 8cd^4 +1 )

We need to distribute the negative over the parentheses:-

= 8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - 2d^5 + c^3d^4 - 8cd^4 -1

Bringing like terms together:

= 8d^5 - 2d^5 - 3c^3d^2 + 5c^2d^3  + c^3d^4 - 4cd^4 - 8cd^4 + 9  

- 1

Simplifying like terms

=  6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8  


8 0
3 years ago
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attashe74 [19]

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Kisachek [45]

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Step-by-step explanation:

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3 years ago
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If rounded 12L
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3 years ago
Read 2 more answers
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