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grin007 [14]
4 years ago
8

A map has a scale of 1 cm : 18 km. Two cities are 2.7 cm apart on the map. To the nearest tenth of a kilometer, what is the actu

al distance corresponding to the map distance?
Mathematics
2 answers:
Kipish [7]4 years ago
5 0
48.6 kilometer is the answer
MrMuchimi4 years ago
4 0

Answer:

The actual distance corresponding to the map distance is 486 kilometer.

Step-by-step explanation:

Given : A map has a scale of 1 cm : 18 km. Two cities are 2.7 cm apart on the map. To the nearest tenth of a kilometer.

To find : What is the actual distance corresponding to the map distance?

Solution :

Let the actual distance corresponding to the map distance is 'x' km.

A map has a scale of 1 cm : 18 km.

Two cities are 2.7 cm apart on the map.

According to question,

\frac{1}{27}=\frac{18}{x}

Cross multiply,

x=18\times 27

x=486

The actual distance corresponding to the map distance is 486 kilometer.

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Which expression would be equivalent to: Which expression would be equivalent to: \frac{1+b}{2} - 3(a-1)
IrinaVladis [17]

Answer:

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}

Step-by-step explanation:

Given

\frac{1+b}{2} - 3(a-1)

Required

An equivalent expression

\frac{1+b}{2} - 3(a-1)

Take LCM

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 2*3(a-1)}{2}

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6(a-1)}{2}

Open bracket

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6a+6}{2}

Collect like terms

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+6+1}{2}

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Hence, an equivalent expression is:

\frac{b- 6a+7}{2}

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