Answer: x = -0.2651 and y = -0.9759
Step-by-step explanation:
Solution by substitution method
8x+5y= -7
-7x+6y= -4 = 7x-6y=4
Suppose,
8x+5y=-7→(1)
7x-6y=4→(2)
Taking equation (1), we have
8x+5y= -7
⇒8x= -5y -7
⇒x= -5y-7 / 8 →(3)
Putting x= -5y-7 / 8
in equation (2), we get 7x-6y=4
7(-5y-7/8)-6y=4
⇒-35y-49-48y=32
⇒-83y-49=32
⇒-83y=32+49
⇒-83y=81
⇒y= 81 / -83
⇒y= -0.9759→(4)
Now, Putting y= -0.9759 in equation (3), we get
x= -5y-7
x= -5(-0.9759)-7/8
⇒x= 4.8795-7/8
⇒x= -2.1205/8
⇒x= -0.2651
∴x= -0.2651 and y = -0.9759
Answer:
42
Step-by-step explanation:
3x^2 +5x
Let x=3
3(3)^2 +5(3)
3*9 +15
27+15
42
I believe the answer is 2. i hope this helps
The best design for this experiment would be a repeated measures design. This is ideal to determine if eating an apple makes you healthy.
<h3>What is an experimental design?</h3>
An experimental design refers to the general structure of an experiment including how people are distributed into the control and experimental group to test a specific phenomenon.
<h3>What is a repeated measures design?</h3>
In a repeated measures design all participants are both parts of the control group, in this case, people who do not eat apples, and the experimental group, or people who eat apples.
<h3>What does this design imply?</h3>
In the case of determining if eating an apple every day, this design implies:
- All participants will be asked to not eat apples every day for a specific period such as one or two months, and health levels will be measured during this time.
- After the first step, all participants will be asked to eat an apple every day during the period, and their health will be measured.
- The researcher can compare the results of each participant, which is more accurate than comparing one participant to another.
Learn more about experiments in: brainly.com/question/1452319
Answer:
a. 
b. 
Step-by-step explanation:
a.


Where, 


Where, 

Volume of the shaded figure = 
b.
expressed in factored form:
Look for the term that is common to 9a³ and 9ab², then take outside the parenthesis.
