Answer:
Step-by-step explanation:
Given:
Slope (m) = ⁴/3
Point on the line = (x, y) = (3, 2)
Required:
Write the equation in slope-intercept form which is y = mx + b
Solution:
Since we know the slope(m), we need to find the y-intercept (b).
This, substitute (x, y) = (3, 2) and m = ⁴/3 into y = mx + b, and solve for b. Thus:
2 = ⁴/3(3) + b
2 = 4 + b
2 - 4 = b
-2 = b
b = -2
To write the equation, substitute m = ⁴/3 and b = -2 into y = mx + b
We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D
Answer:
you have to take your rule and make a right angle by connecting the points of the ordinate and abscisses
the answer is 1 ( constant of proportionality)
Answer:
The sector of the given circle is IKLV
Step-by-step explanation:
Given as :
The figure shown is the circle
The circle have chord as UT and VT
Both chords UT and VT meets at points T outsides the circle , and intersect the circle at Y and I
Now,
Points L and I are on the circle with center K
The line is drawn joining center K and point L as KL which is the radius
The line is drawn joining center K and point I as KI which is the radius
Now, A sector is the area enclosed by two radius and arc
So, here KL and KI are two radius and LI is the arc
So, IKLV is the sector
Hence the sector of the given circle is IKLV . Answer
90
the answer is 90 but the answer i give has to be over 20 characters so i'm typing random things. have a good day:)
