Answer:
The answer is option (C). The width of the rectangle=6 inches
Step-by-step explanation:
<em>Step 1: Determine the dimensions of the rectangle</em>
width=w
length=w+6
<em>Step 2: Determine the perimeter of the rectangle</em>
P=2(L+W)
where;
P=perimeter
L=length
W=width
In our case;
P=36 inches
L=w+6
w=w
replacing;
2(w+w+6)=36
2(2 w+6)=36
4 w+12=36
4 w=36-12=24
4 w=24
w=24/4=6
W=6 inches
L=6+6=12 inches
The width of the rectangle=6 inches
Problem: 7/10 - 1/2
1/2 = x/10 Find the common denominator
1/2 = 5/10
Subtract the numerators
7-5
Answer: 2/10
Simplest form: 1/5
Answer:
ok so if equilateral triangle has 1 inch and box has 9 inch of height, the lateral area would be 27 square-inch
Step-by-step explanation:
<span>The theorems in this lesson relate to all of the following (tangents, arcs, and chords) except for <u>radii.</u></span>
Answer:
6
Step-by-step explanation:
Since the degree of the angle is 45, we know that the triangle is isosceles. That means that the sides of the triangle, not including the hypotenuse, has a length of 3√2.
Using the Pythagorean theorem, which is a^2 + b^2 = c^2, we have (3√2)^2 + (3√2)^2 = c^2.
Note: c is the hypotenuse of the triangle.
18 + 18 = c^2
= 36 = c^2
Therefore, c = 6.
