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ELEN [110]
3 years ago
9

The area of the irregular polygon is ____ square units.

Mathematics
2 answers:
krok68 [10]3 years ago
8 0
To find the area of this shape youd have to break it up. If you broke it into the left section and the right bottom section youd get 2 rectangles and the area of a rectangle is defined as A=Length*Width. The left would be a 3*4 rectangle making its area 12 units^2 and the right would have a height of (3-2) units and a length of (7-4) units making its area 1*3 or just 3 units^2, if you add both areas you get the total area, which is 15 units^2
kodGreya [7K]3 years ago
8 0
Break it up into chunks: the small rectangle and the big rectangle.
subtract 7 and 4 to get the big side of the rectangle, and subtract 3 and 2 to get the small side. then find the area of the big rectangle and small rectangle to get the area of the entire rectangle. area equals 15 units^2
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BlackZzzverrR [31]

The solution is attached as a word file.

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garik1379 [7]

Answer:

d=1.28\times 10^{-6}\ g/cm^3

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d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3

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