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svetoff [14.1K]
3 years ago
15

What is the answer for I=E/R for E

Mathematics
1 answer:
Elden [556K]3 years ago
7 0

http://lianmath.com/describe-a-serie-of-shifts-that-translates-the-graph-yx-93-4-back-onto-the-graph-of-yx-3/


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Find the value of x. Round your answer to the nearest tenth.
Fantom [35]
Hello again! So we will be using the pythagorean theorem (leg^2+leg^2=hypotenuse^2) to solve for the bottom leg of the triangles. After we do that, we'll subtract the value of the legs from 31, and that'll be x.


Plug in 17 and z (or any variable that isn't x) into the leg variable and 19 into the hypotenuse variable, and from there we can solve.

17^2+z^2=19^2

Solve the exponents to get 289+z^2=361

Subtract 289 on each side to get z^2=72

Lastly, square root each side of the equation and your answer should be z= \sqrt{72} (To get more accurate answers, you shouldn't round until the end of the problem)


Nextly, we will need to subtract \sqrt{72} from 31. And since there are 2 triangles, you'll need to multiply \sqrt{72} by 2.

x=31- \sqrt{72} *2 \\ x=14.0

In short, x = 14.0
5 0
3 years ago
Which of the following graphs shows the solution set for the inequality below?<br> |x + 3|+ 7 &gt; 8
uranmaximum [27]

Answer:

Step-by-step explanation:

|x+3|+7>8

|x+3|>8-7

|x+3|>1

either x+3>1

x>2

or x+3<-1

x<-4

7 0
3 years ago
John is trying to find the relationship between a student's age and the number of pets that he or she owns. He collects data fro
LenaWriter [7]
Positive

Explanation: I’m guessing as you get older, you get more responsible, so you have more pets
3 0
3 years ago
Look at image to get the questions
Sergeu [11.5K]

Answer:

Step-by-step explanation:

What do you have to do solve it or what

5 0
3 years ago
Determine the domain:<br><br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7Bln%28ln%28x%20%2B%201%29%29%7D%7Be%
Xelga [282]

The denominator cannot be zero, so

e^x - 9 = 0 \implies e^x = 9 \implies x = \ln(9)

is not in the domain of f(x).

\ln(x) is defined only for x>0, and we have

\ln(x+1) > 0 \implies e^{\ln(x+1)} > e^0 \implies x+1 > 1 \implies x>0

so there is no issue here.

By the same token, we need to have

x+1 > 0 \implies x > -1

Taking all the exclusions together, we find the domain of f(x) is the set

\left\{ x \in \Bbb R \mid x > 0 \text{ and } x \neq \ln(9)\right\}

or equivalently, the interval (0,\ln(9))\cup(\ln(9),\infty).

3 0
2 years ago
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