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3 years ago

13

A relation is plotted as a linear function on the coordinate plane starting at point E at

2 answers:

Jobisdone [24]3 years ago

4 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 0}} &,&{{ 27}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ -8}}~)
\end{array}
\\\\\\
% slope = m
\stackrel{\stackrel{average}{rate~of~change}}{slope}= {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-8-27}{5-0}\implies \cfrac{-35}{5}\implies -7$

well, when x = 0, namely at the very beginning, y = 27, thus, that IS the initial value.

nevsk [136]3 years ago

3 0

Answer:

x= -7 and y= 27.

Step-by-step explanation:

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3 years ago

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3 years ago

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28,543

Step-by-step explanation:

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Please write down your work on the loose leaf, take a CLEAR picture, and upload here. Thank you.

Zigmanuir [339]

Answer:

m(∠C) = 18°

Step-by-step explanation:

From the picture attached,

m(arc BD) = 20°

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Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.

m(∠C) = $\frac{1}{2}[\text{arc(EA)}-\text{arc(BD)}]$

Since, AB is a diameter,

m(arc BD) + m(arc DE) + m(arc EA) = 180°

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Therefore, m(∠C) = $\frac{1}{2}(56^{\circ}-20^{\circ})$

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3 years ago