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3 years ago

A relation is plotted as a linear function on the coordinate plane starting at point E at

2 answers:

4 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 0}} &,&{{ 27}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ -8}}~)
\end{array}
\\\\\\
% slope = m
\stackrel{\stackrel{average}{rate~of~change}}{slope}= {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-8-27}{5-0}\implies \cfrac{-35}{5}\implies -7$

well, when x = 0, namely at the very beginning, y = 27, thus, that IS the initial value.

nevsk [136]3 years ago

3 0

Answer:

x= -7 and y= 27.

Step-by-step explanation:

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Step-by-step explanation:

We have the following info given:

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$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

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