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Anna11 [10]
3 years ago
13

A relation is plotted as a linear function on the coordinate plane starting at point E at

Mathematics
2 answers:
Jobisdone [24]3 years ago
4 0
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 0}} &,&{{ 27}}~) 
%  (c,d)
&&(~{{ 5}} &,&{{ -8}}~)
\end{array}
\\\\\\
% slope  = m
\stackrel{\stackrel{average}{rate~of~change}}{slope}= {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-8-27}{5-0}\implies \cfrac{-35}{5}\implies -7

well, when x = 0, namely at the very beginning, y = 27, thus, that IS the initial value.
nevsk [136]3 years ago
3 0

Answer:

x= -7 and y= 27.

Step-by-step explanation:


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The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun
Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. \mu=12.30 and \sigma=0.20

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process =  probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587

Hence, the required probability= A) 0.1587

6 0
3 years ago
Point G is on line segment{FH}
Angelina_Jolie [31]

Answer:

FG = 7

Step-by-step explanation:

5x+2+3x-1=9

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x = 1

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Please help with math
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What would you need help with?

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