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Svet_ta [14]
3 years ago
11

What is the sum of 9c+(8+3c)?

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0
<span>9c+(8+3c)      
9c+8+3c     (collect like terms)

9c+3c+8
12c+8

12c+8 is the answer.
im not sure if your teacher also wants the answer to be in simplest form so im going to do that below as well:

12c+8      (4*3=12 and 4*2=8. you can take out a 4 from those 2 numbers)

4(3c+2) (this is the simplest form of </span>9c+(8+3c)<span>)


</span>
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Round 68,413 to the nearest thousand
meriva
8 is in the thousands place.

Look to the number in the hundreds (right next to it). It is a 4. Because 4 is less than 5, round down.

68413 rounded down in the thousands place becomes 68000

68000 is your answer


hope this helps
5 0
3 years ago
(x+4) (x+10)<br>simplify​
Murrr4er [49]

Answer:

x^2 + 14x + 40.

Step-by-step explanation:

(x+4) (x+10)

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8 0
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3 years ago
If the measure of angle 3 is 80 degrees and the measurer of angle 6 is (2x)
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Answer:
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5 0
2 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
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Answer:

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The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
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