All categories

2 years ago

The main source of a hurricane's energy comes from _____. heat water wind land

Physics

2 answers:

KatRina [158]2 years ago

7 0

Answer:The actual answer is heat.

Explanation:There is always water under a forming hurricane, the strength of the hurricane depends on the heat of the water since heat is a raw form of energy. It can transfer to the storm.

vova2212 [387]2 years ago

6 0

Answer: latent heat of water

Explanation: the hurricane pulls more strength to it self by drawing surface air towards it's low pressure center

You might be interested in

A device that does work with one movement and changes the size or direction of a force is a(n)

tresset_1 [31]

A device that does work with one movement and changes the size or direction of a force is a simple machine.

7 0

3 years ago

Read 2 more answers

The ratio of output power to input power, in percent, is called?

Harrizon [31]

That's efficiency. There's no law that it must be stated in percent.

4 0

2 years ago

Read 2 more answers

A bicycle is a compound machine, true or false

JulsSmile [24]

This is true. The break handles and brakes are levers and the seat adjustment (raise or lower) is a screw.

5 0

3 years ago

Read 2 more answers

What is the frequency, in units of kiloHertz, of an AC waveform that has a period of 12 microseconds?

Alik [6]

Answer:

83.3 kHz

Explanation:

The frequency of a waveform is equal to the reciprocal of its period:

$f=\frac{1}{T}$

where

f is the frequency

T is the period

In this problem, we have

$T=12 \mu s=12\cdot 10^{-6} s$

so, the frequency of the waveform is

$f=\frac{1}{12 \cdot 10^{-6} s}=8.33\cdot 10^4 Hz$

And by converting into kiloHertz,

$f=8.33\cdot 10^4 Hz=83.3 kHz$

3 0

2 years ago

A shot-putter released the shot at an angle of 41.5 degrees and a height of 1.9 m with an initial velocity of 13.3 m/s. How far

liq [111]

Answer:

x = 17.88[m]

Explanation:

We can find the components of the initial velocity:

$(v_{x})_{o} = 13.3*cos(41.5)=9.96[m/s]\\(v_{y})_{o} = 13.3*sin(41.5)=8.81[m/s]$

We have to remember that the acceleration of gravity will be worked with negative sign, since it acts in the opposite direction to the movement in direction and the projectile upwards.

g = - 9.81[m/s^2]

Now we must find the time it takes for the projectile to hit the ground, as the problem mentions that it does not impact on the board.

$y=y_{o} +(v_{y} )_{o} *t-0.5*g*(t)^{2} \\0=1.9+(8.81*t)-(4.905*t^{2})\\-1.9=8.81*t*(1-0.5567*t)\\t=0\\t=1.796[s]$

With this time we can calculate the horizontal distance:

$x=(v_{x})_{o} *t\\x=9.96*1.796\\x=17.88[m]$

3 0

3 years ago