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2 years ago

What can be found in a compost bin?

Physics

2 answers:

Angelina_Jolie [31]2 years ago

6 0

D.All of the above is the correct Answer

BigorU [14]2 years ago

5 0

D. all of the above

Hope this helps!

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A constant current I circulates counterclockwise around a wire loop in the shape of a triangle, lying in x-y plane, with vertice

Blizzard [7]

Answer:

Considering a triangle like the one of the figures, you can obtain the total magnetic force applied on it like the addition of the forces applied to each of the 3 sides.

Been the magnetic force formula:

$F=\int\limits^a_b {I} \, \overline {dx} \times \overline {B}$

For each segment:

Segment 1 (from [0,0,0] to [a,0,0]):

$F=\int\limits^a_0 {I} \, \overline {x}dx \times B \overline {z}=-IBa\overline {y}$

Segment 2 (from [a,0,0] to [0,a,0]):

$F=\int\limits^{(0,a)}_{(a,0)} {I} \, \frac{\sqrt{2} }{2} (\overline {x}+\overline {y})dx \times B \overline {z}=IB2a(\overline {x}+\overline {y})$

Segment 3 (From [0,a,0] to [0,0,0]):

$F=\int\limits^0_a {I} \, \overline {y}dx \times B \overline {z}=-IBa\overline {x}$

Total force on the wire loop:

$F_{T} =F_{1} +F_{2} +F_{3} =-IBa\overline {y}+IB2a(\overline {x}+\overline {y})-IBa\overline {x}=0N$

5 0

2 years ago

A student in gym class swings from a rope and they are moving 5 m/s at the bottom of their swing. What is the height they reach

vaieri [72.5K]

Answer:

Explanation:

4 0

2 years ago

HELP ;

mestny [16]

Answer:

The frequency would double.

Explanation:

Given:

Speed of wave (v) = constant.

Frequency of wave initially (f₁) = 2 Hz

Initial wavelength of the wave (λ₁) = 1 m

Final wavelength of the wave (λ₂) = 0.5 m

Final frequency of the wave (f₂) = ?

We know that the product of wavelength and frequency of the wave is equal to the speed of the wave.

Therefore, framing in equation form, we have:

Wavelength × Frequency = Speed

$\lambda\times f=v$

It is given that speed of the wave remains the same. So, the product must always be a constant.

Therefore,

$\lambda\times f=constant\ or\ \\\lambda_1\times f_1=\lambda_2\times f_2$

Now, plug in the given values and solve for 'f₂'. This gives,

$1\times 2=0.5\times f_2\\\\f_2=\frac{2}{0.5}=4\ Hz$

Therefore, the final frequency is 4 Hz which is double of the initial frequency.

f₂ = 2f₁ = 2 × 2 = 4 Hz

So, the second option is correct.

7 0

3 years ago

Read 2 more answers

A cheetah runs at a speed of 27.6 m/s. If the

aleksklad [387]

Answer:

256.68m

Explanation:

that is the procedure above

8 0

2 years ago

The tension in cable da has a magnitude of tda=6.27 lb. find the cartesian components of tension tda, which is directed from d t

Oliga [24]

Complete Question

The Complete Question is attached below

We have that the Cartesian components of tension $T_{da}$ is

$T_{DA}=-4.433i-3.49j+2.735k$

From the Question we are told that

$M_{da}=6.27 lb\\\\w=9.50ft\\\\d=6.60ft\\\\h=4.50ft$

$\vec {DA}=-4.7i-3.7j+2.9k)ft$

$\vec {DB}=-1.9i-3.7j+1.9k)ft\\\\\vec {DC}=-1.9i+5.8j-1.6k)ft$

Generally the equation for $T_{DA}$ is mathematically given as

$T_{DA}=\phi_{DA}* M_{da}$

Where

$\phi_{DA}=\frac{-4.7i-3.7j+2.9k}{(-4.7)^2+(-3.7)^2+(2.9)^2}\\\\\phi_{DA}=\frac{-4.7i-3.7j+2.9k}{6.65}$

Therefore

$T_{DA}=\phi_{DA}* M_{da}$

$T_{DA}=\frac{-4.7i-3.7j+2.9k}{6.65}* 6.27$

$T_{DA}=-4.433i-3.49j+2.735k$

For more information on this visit

brainly.com/question/20746649?referrer=searchResults

5 0

2 years ago