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Svetlanka [38]
3 years ago
10

Please help with slope!

Mathematics
1 answer:
hjlf3 years ago
4 0
The rise over run is 3/2 but since it's backward it would be -3/2
Y-Intercept at 3
So your equation is 
y = -3/2 + 3
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If you doubled joes age and added 10 years he would still be younger than his uncle. His uncle is 51. Use inequalities to find h
CaHeK987 [17]

Answer:

He is 20 at oldest, or x\leq 20

Step-by-step explanation:

The first step in finding a possible age is:

Subtract 10 from 51, and you get 41. Divide by 2, and you get about 20.5.

This means Joe is younger than or 20 years old.

4 0
2 years ago
How many, whole numben are there between<br>32 and 53 ?​
Ulleksa [173]

Answer:

21

Step-by-step explanation:

5 0
3 years ago
8*4+32-44+1+1+1+1+1+1
Bas_tet [7]

Answer:

26

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Simplify the expression by combining like terms:<br><br> 4n+4(2n+3)
Anna007 [38]
First, you do the distributive property on:

4(2n+3)

You would get

8n+12

Then add the original part of the equation in (4n)

4n+8n+12

Combine like terms

12n+12 is the answer
7 0
3 years ago
Read 2 more answers
Match the equations with their solutions over the interval [0, 2π].
nignag [31]

I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs are:

cos(x)tan(x) – ½ = 0 → π/6 and 5π/6

cos(π/6)tan(π/6) – ½ = 0

cos(5π/6)tan(5π/6) – ½ = 0

 

sec(x)cot(x) + 2 = 0 → 7π/6 and 11π/6

sec(7π/6)cot(7π/6) + 2 = 0

sec(11π/6)cot(11π/6) + 2 = 0

 

sin(x)cot(x) + 1/sqrt2 = 0 → 3π/4 and 5π/4

sin(3π/4)cot(3π/4) + 1/sqrt2 = 0

sin(5π/4)cot(5π/4) + 1/sqrt2 = 0

 

csc(x)tan(x) – 2 = 0 → π/3 and 5π/3

csc(π/3)tan(π/3) – 2 = 0

csc(5π/3)tan(5π/3) – 2 = 0

5 0
3 years ago
Read 2 more answers
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