Answer: B or C
Step-by-step explanation:
if u can compare the triangles u u can use ur math and get the answer
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
Answer:
237
Step-by-step explanation:
This is a system of equations.
The theater sold 364 adult and child tickets, so a + c = 364
They made a total of $1930. Each adult ticket was $6 & child tickets were $4. The second equation is 6a + 4c = 1930.
Let's line them up
a + c = 364
6a + 4c = 1930
Since we need to solve for the number of adult tickets, we want to get rid of the c variable. I'm going to multiply the entire first equation by -4 to do this. The second equation stays the same. Now, I have:
-4a - 4c = -1456
6a + 4c = 1930 Add them together
----------------------
2a = 474 Divide by 2 to solve for a
a = 237
There were 237 adult tickets sold
Answer:
it would be a closed circle and to the right
Step-by-step explanation:
I have a little tip whenever the greater or less than sign is underlined it will always be closed, and when x is greater than -4.5 all the numbers that are greater than -4.5 will be on the right side so that will be your answer.
