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babunello [35]
2 years ago
14

A line has a rise of 6 and a slope of 1/20.

Mathematics
1 answer:
natima [27]2 years ago
6 0

Answer:

120

<h2>Trust me it is correct</h2><h2>Good Luck:)</h2>
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Roland is purchasing pottery supplies for his pottery class. He buys a portable pottery wheel for $382 modeling clay is $12, and
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To find the total cost of Roland's purchases, you will add $382 plus $12 plus $16.14 together to find the total spent.

$410.14.

Next will be to calculate the new price based on the sales tax rate. To do this you will multiply the cost by 1.0825. This includes everything you paid and the sales tax

410.14 x 1.0825 = $443.98

Roland's total price was $443.98.
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V125BC [204]

Answer:No

Step-by-step explanation:

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S(n) = 3n + 4, n = { 1, 2, 3, 4 }
valkas [14]
7, 10, 13, 16 and so on
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2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Crm%20%20%5Clim_%7Bk%20%5Cto%20%5Cinfty%20%7D%20%5Csqrt%5B%20%20k%5D%7B%20%5CGamma%20%
Naddik [55]

We have

\sqrt[k]{\Gamma\left(\dfrac1k\right) \Gamma\left(\dfrac2k\right) \cdots \Gamma\left(\dfrac kk\right)} \\\\ = \exp\left(\dfrac{\ln\left(\Gamma\left(\dfrac1k\right) \Gamma\left(\dfrac2k\right) \cdots \Gamma\left(\dfrac kk\right)\right)}k\right) \\\\ = \exp\left(\dfrac{\ln\left(\Gamma\left(\dfrac1k\right)\right)+\ln\left( \Gamma\left(\dfrac2k\right)\right)+ \cdots +\ln\left(\Gamma\left(\dfrac kk\right)\right)}k\right)

and as k goes to ∞, the exponent converges to a definite integral. So the limit is

\displaystyle \lim_{k\to\infty} \sqrt[k]{\Gamma\left(\dfrac1k\right) \Gamma\left(\dfrac2k\right) \cdots \Gamma\left(\dfrac kk\right)} \\\\ = \exp\left(\lim_{k\to\infty} \frac1k \sum_{i=1}^k \ln\left(\Gamma\left(\frac ik\right)\right)\right) \\\\ = \exp\left(\int_0^1 \ln\left(\Gamma(x)\right)\, dx\right) \\\\ = \exp\left(\dfrac{\ln(2\pi)}2}\right) = \boxed{\sqrt{2\pi}}

6 0
1 year ago
I need help with this math problem ASAP please an explanation too
Rufina [12.5K]

Answer:

the answer is 300

Step-by-step explanation:

4 0
2 years ago
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