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3 years ago

Please solve for w, p=21+2w

Mathematics

1 answer:

sp2606 [1]3 years ago

3 0

Answer:

w = (p - 21)/2

Step-by-step explanation:

Rearrange the equation so that it is equal to w.

p = 21 + 2w

p - 21 = (21 + 2w) - 21

p - 21 = 2w

(p - 21)/2 = (2w)/2

(p - 21)/2 = w

w = (p - 21)/2

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A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is $\frac{1}{2}$ , in the second is $\frac{1}{4}$ , in the third is $\frac{1}{8}$ and so on. Then, P(C) is given by the next sum:

$P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1$

This is a geometric series with factor $\frac{1}{2}$ . Then is convergent to $\frac{1}{1-\frac{1}{2}}-1=1.$ . With this we have proved that P(C)=1.

Now, observe that

$P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.$

Then

$P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}$

$P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}$

$P(C1\cap C2)=P(TTTTH)=\frac{1}{32}$

and

$P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}$

5 0

3 years ago

1/3(6z+7.2)=0.5(8z+2)-0.4 please hurry this is for now

Crazy boy [7]

Answer:

z = - 0.78

Step-by-step explanation:

Given:

1/3(6z+7.2)=0.5(8z+2)-0.4

Open parenthesis

2z + 2.4 = (4z + 1) - 0.4

2z + 2.4 = - 1.6z - 0.4

Collect like terms

2z + 1.6z = - 0.4 - 2.4

3.6z = -2.8

z = -2.8 / 3.6

= - 0.78

3 0

3 years ago

HELPPP ILL GIVE 70 POINTS!!!!!

MrRissso [65]

Answer:

It will take 4.71 hours to travel a distance of 221.43 miles

Step-by-step explanation:

Given

Distance covered in time 7.99 hours is 375.32 miles.

Now we know that speed is equal to distance per unit time.

Therefore,

$speed = \frac{distance}{time} \\= \frac{375.32}{7.99}\\=46.97\ mi/h$

Which is the constant speed, hence now time taken for a distance of 221.43 miles will be

$time = \frac{distance}{speed} \\=\frac{221.43}{46.97} \\=4.71\ h$

Therefore, the time taken to cover 221.43 miles is 4.71 hours.

6 0

3 years ago

If 3t - 7 = 5t, then 6t =

STALIN [3.7K]

Answer:

-21 = 6t

Step-by-step explanation:

3t - 7 = 5t

Subtract 3t from each side

3t-7-3t = 5t-3t

-7 = 2t

Multiply each side by 3 to get 6t

-7*3 = 2t*3

-21 = 6t

6 0

4 years ago

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Which of the following situations could be described by the equation y = 120 - 25x?

Otrada [13]

Answer:

Is there any other information?

Step-by-step explanation:

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3 years ago