Molar mass Argon ( Ar ) = 39.95 g/mol
39.95 g ---------------- 6.02 x 10²³ atoms
0.377 g ---------------- ( atoms Ar )
( atoms Ar ) = 0.377 x ( 6.02 x 10²³ ) / 39.95
( atoms Ar ) = 2.26954 x 10²³ / 39.95
= 5.68 x 10²¹ atoms Ar
hope this helps!
Answer: The mass is 348.8g
Explanation:
We begin by using Avogadro's number to convert the number of molecules of Sodium Hydroxide to moles.
6.02 x 10∧23 molecules of NaOH -------> 1 mole of NaOH
∴ 5.25 x 10∧24 molecules of NaOH -------> 1/ 6.02 x 10∧23 x 5.25 x 10∧24 =
8.72moles.
Having found the number of moles, we then move from moles to gram by using the molar mass of NaOH (i.e the mass of 1 mole of NaOH).
1 mole of NaOH is equivalent to 40g (Molar Mass)
8.72 moles of NaOH would be equivalent to; 40/ 1 x 8.72 = 348.8g
The mass in 5.25 x 10∧24molecules of NaOH is 348.8g
Answer:
The temperature at 581.2 mL volume was 242.8 K.
Explanation:
Using Charle's law
Given ,
V₁ = 581.2 mL
V₂ = 830.5 mL
T₁ = ?
T₂ = 347 K
Using above equation as:
<u>The temperature at 581.2 mL volume was 242.8 K.</u>
Those Hydrogen atoms which are present at alpha position to carbonyl group are mildly acidic in nature. When such acidic proton containing carbonyl compounds are treated with strong base, they yield enolates. The negative charge created on alpha carbon resonates and shifts to carbonyl oxygen resulting in formation of carbon double bond carbon.
In <span>tert−butyl methyl ketone there are two carbons at each alpha position. Among these two carbons only methyl carbon contains hydrogen atoms while the second one is bonded to further three carbons making it Quaternary carbon. The base abstracts proton from methyl group and enolate is formed.
</span>tert−butyl methyl ketone in this case acts as acid, Hydroxyl ion acts as base, while the enolate generated is the conjugate base of <span>tert−butyl methyl ketone and Water produced is the conjugate acid of hydroxide ion.</span>