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AnnyKZ [126]
3 years ago
13

Simplify the expression -9(-6+2n)

Mathematics
2 answers:
Wittaler [7]3 years ago
8 0
54 - 18n

Multiply -9 by -6 to get 54.
Multiply -9 by 2n to get 18n.
enyata [817]3 years ago
6 0

Answer:

-18n+54

Step-by-step explanation:

-9 has to be multiplied on each side

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Answer:

x = - 6 or x = 2

Step-by-step explanation:

The absolute value function always returns a positive value. However, the expression inside can be positive or negative.

Given

| 2x + 4 | - 1 = 7 ( add 1 to both sides )

| 2x + 4 | = 8, thus

2x + 4 = 8 ( subtract 4 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

OR

-(2x + 4) = 8

- 2x - 4 = 8 ( add 4 to both sides )

- 2x = 12 ( divide both sides by - 2 )

x = - 6

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

x = 2 → | 4 + 4 | - 1 = | 8 | - 1 = 8 - 1 = 7 ← True

x = - 6 → | - 12 + 4 | - 1 = | - 8 | - 1 = 8 - 1 = 7 ← True

Hence the solutions are x = - 6 or x = 2

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A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar
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Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ​ounces, with a sample standard deviation of 0.052 ounces.

Let \mu = <u><em>population mean amount packaged. </em></u>

So, Null Hypothesis, H_0 : \mu = 8.17 ounces    {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, H_A : \mu\neq 8.17 ounces    {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample mean amount dispensed = 8.171 ounces

             s = sample standard deviation = 0.052 ounces

            n = sample of packages = 50

So, <u><em>the test statistics</em></u> =  \frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }  ~   t_4_9

                                    =  0.1359  

The value of t-test statistics is 0.1359.

<u>Also, the P-value of test-statistics is given by;</u>

the meaning of the​ p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

                    P-value = P( t_4_9 > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

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