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Roman55 [17]
3 years ago
6

Find the smallest possible interger value n for which 99n is a multiple of 24

Mathematics
2 answers:
anastassius [24]3 years ago
8 0
Thats going to be 3 cos 3 * 8 and 3 times 23 is both of the answers
motikmotik3 years ago
3 0
I would guess that you would need to find the Least Common Multiple (LCM) of 99 and 24 first. 

After listing out all of the multiples, you would have 792 be the LCM of 99 and 24. But since we need to find the integer value of n, in 99n (which means 99 x n), then we need to divide 792 by 99, which would be 8.

n = 8 
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A model rocket is launched directly upward at a speed of 50 meters per second from a height of 8 meters. The function f(t)=−4.9t
Gnoma [55]

Answer:

t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36

t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158

And since the time can't be negative we have that:

t= 10.36 seconds

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

Step-by-step explanation:

For this case we have the function of the height in terms of the time givenby:

h(t) = -4.9t^2 +50 t+8

And we want to known when the rockect hit the ground and for this case we need to solve the equation h=0

-4.9t^2 +50 t+8 =0

And as we can see we have a quadratic equation like this one:

ax^2 +bx+c

Where: a =-4.9 , b =50 c =8

And the general solutions are given by:

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

If we replace the values that we have we got:

t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36

t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158

And since the time can't be negative we have that:

t= 10.36 seconds

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

6 0
4 years ago
Simplify ; 7a+5b-5a-6b
serious [3.7K]
The answer for this is 2a-b
8 0
3 years ago
Please help me solve this question...
const2013 [10]

Answer: It would be 30 each, so 30 plus laura being three years older = 103 so you answer is 30

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the Precision for each measurement. <br> 40 feet? 12cm? 9 1/2in.?
iris [78.8K]

precision for 40 feet is 1/2 foot

12 cm is 1/2 cm

 for 9 1/2 in is 1/4 in

8 0
3 years ago
I need to be able to take a set of data, and find it's exponential function.​
N76 [4]

Answer:

The process below should work.

Step-by-step explanation:

Let's pretend we have these two points we are trying to find an exponential equation for:  (-2,6) and (2,1).

Exponential equations are of the form y=a \cdot b^x where we must find a and b.

So you enter both points into that equation giving you:

6=a \cdot b^{-2}

1=a \cdot b^{2}

I'm going to divide equation 1 by 2 because if I do the a's will cancel and I could solve or b.

\frac{6}{1}=\frac{a \cdot b^{-2}}{a \cdot b^2}

6=\frac{b^{-2}}{b^2}

By law of exponent, I can rewrite the right hand side:

6=b^{-2-2}

6=b^{-4}

Now do ^(-1/4) on both sides to solve for b:

6^\frac{-1}{4}=b

Now we use one of the equations along with our value for b to find a:

1=a \cdot b^2 with b=6^{\frac{-1}{4}}

1=a \cdot (6^{\frac{-1}{4}})^2

Simplify using law of exponents:

1=a \cdot 6^{-\frac{1}{2}}

Multiply both sides by 6^(1/2) to solve for a:

6^{\frac{1}{2}}=a

y=a \cdot b^x with a=6^{\frac{1}{2}} \text{ and } b=6^{\frac{-1}{4}} is:

y=6^\frac{1}{2} \cdot (6^{\frac{-1}{4})^x

We can simplify a smidgen:

y=6^\frac{1}{2} \cdot (6)^\frac{-x}{4}

7 0
4 years ago
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