Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer:Third one
Step-by-step explanation:
Answer:
0.2
Step-by-step explanation:
hope this helps you. have a good day
The last one because the base is a square
Answer:
The next number is 1321232112
Step-by-step explanation:
32 is read off as "one 3, one 2" = 1312
1312 is read off as "one 1, one 3, one 1, one 2" = 11131112
11131112 is read off as "three 1s, one 3, three 1s, one 2" = 31133112
31133112 is read off as "one 3, two 1s, two 3s, two 1s, one 2" = 1321232112
