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Bezzdna [24]
3 years ago
9

The diameter of a ping pong ball is 4.0cm. find the length in kilometers of a row of 6.02×1023 ping pong balls.

Mathematics
2 answers:
Sindrei [870]3 years ago
7 0
Let ping pong ball be called PPB
 To solve this problem you must know the following unit change
 1km = 1000m
 1m = 100cm
 Then, applying the change of units, we have that the length in kilometers is:
 6.02x10 ^ 23PPB x 4.0cm / 1PPB x 1m / 100cm x 1km / 1000m = 2.41 x 10 ^ 19 km
Vikentia [17]3 years ago
3 0
The length is determined by multiplying the number of balls with the diameter. The answer that would come out of this is in units of centimeters.

    L = (6.02 x 10^23 balls)(4 cm/ball)
    L = 2.408 x 10^24 cm

Then, we use the proper conversion factor to convert centimeter to kilometer.

     L = (2.408 x 10^24 cm)(1 m/100 cm)(1 km/1000 m)
       L = (2.408 x 10^24)(10^5)
        

The answer to this item is 2.408 x 10^19 km. 
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Complete Question

Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.

Answer:

Yes it is  possible to take the  9 children and 4 adults to both shows

Step-by-step explanation:

From the question we are told that

    The  cost of the Matinee tickets for a child is  z =  $4

    The  cost of the Matinee tickets for an adult is  a  = $ 4

     The cost of the Evening tickets for  a child is  k =  $6

      The cost of the Evening tickets for an adult is  b =  $8    

      The  maximum amount to be spent on Matinee tickets is  m = $80

       The maximum amount to be spent on Evening tickets is  e =  $100

       The  number of child to be taken to the movies is  n  = 9

        The number of adults to be taken to the movies is  j  =  4

Now the total amount of money that would be spent on Matinee tickets is  mathematically evaluated as      

           t = 4 n + 4 j

substituting values

           t = 4 *  9  + 4* 4

           t =  52

Now the total amount of money that would be spent on  Evening ticket is mathematically evaluated as      

      T =  6n + 8j

substituting values

     T =  6(9) + 8(4)

    T = 86

This implies that it is possible to take 9 children and 4 adults to both shows

given that

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and  

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i.e   $ 86 \le $ 100

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