Quoteint of powers
(x^m)/(x^n)=x^(m-n)
we know that 8=x^3
so
(2^5)/8=2^2 can be rewritten as
(2^5)/(2^3)=2^2
and 5-3=2 so it's true
answer is
third one
by simplifieng 8 to 2^3 to make both powers base two, and subtraction the exponents
Answer:
3 – i hope i helped :)))))
Step-by-step explanation:
Answer: 60, but I got other answers to but 60 was my first.
sorry if wrong.
Step-by-step explanation:
Add 6 7 and two you get 15 xy subtract -11 and -4 you get positive 7xy add 15 and 7 and you get 22xy
