Answer:
<h2><em><u>120</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em></h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u>, </u></em>
Base of the parallelogram = 10
Height of the parallelogram = 12
<em><u>Therefore</u></em><em><u>, </u></em>
Area of the parallelogram = <em>base</em><em> </em><em>×</em><em> </em><em>height</em><em> </em>
= 10 × 12
= 120
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>Area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>parallelogram</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>120</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Answer:
1. D
2. A
3. C
4. A
Step-by-step explanation:
Wouldn't you just do 10 divided by 12
From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent.
Answer:
So if a line was parallel it would have same slope. You can search up what slope-intercept form means. But if you have an equation like this:
y = mx+b
The slope will be m. Your question is written in the form. 2/5 = m.
The slope is 2/5
The y-intercept is 4/5
