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Butoxors [25]
3 years ago
11

Giving 45 points! I need help!

Mathematics
1 answer:
Monica [59]3 years ago
8 0

where is the question?

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I can send you pictures
Ivanshal [37]
Of the question or answer
6 0
3 years ago
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The area of the triangle is 1560 m2<br><br>True<br><br>False
ValentinkaMS [17]

Answer:

FALSE

Step-by-step explanation:

Area of triangle is given by formula :

Area\ =\ \frac{1}{2}\left(base\right)\left(Altitude\right)

From picture we see that Altitude = 60 m

Base = 52 + 71 = 123 m

Now plug these values into above formula:

Area\ =\ \frac{1}{2}\left(123\right)\left(60\right)

Area\ =\ \frac{1}{2}\left(15129\right)

Area\ =\ \frac{15129}{2}

Area\ =\ 7564.5

Which is different than given area 1560 m^2.

Hence answer is FALSE.

8 0
3 years ago
What are the coordinates of the image of the point (1-, 2) under a dilation of 3 with the origin
Gemiola [76]

Answer:

The image of the point (1, -2) under a dilation of 3 is (3, -6).

Step-by-step explanation:

Correct statement is:

<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>

From Linear Algebra we get that dilation of a point with respect to another point is represented by:

\vec P' = \vec R + r\cdot (\vec P-\vec R) (Eq. 1)

Where:

\vec R - Reference point with respect to origin, dimensionless.

\vec P - Original point with respect to origin, dimensionless.

r - Dilation factor, dimensionless.

If we know that \vec R = (0,0), \vec P = (1, -2) and r = 3, then the coordinates of the image of the original point is:

\vec P' = (0,0) +3\cdot [(1,-2)-(0,0)]

\vec P' = (0,0) + 3\cdot (1,-2)

\vec P' = (3,-6)

The image of the point (1, -2) under a dilation of 3 is (3, -6).

4 0
3 years ago
I need help siwjjwnwnjsb ejwjennejejejene
makvit [3.9K]
The answer is 3 hope this helps
3 0
3 years ago
What is the equation of the line shown written in slope-intercept form?
Nataly [62]
It would be Y=2 as it's a horizontal line at y=2
6 0
3 years ago
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