Answer:
The equation of line passing through points (1 , 4) and (3 , - 4) is y = - 4 x + 8
Step-by-step explanation:
Given as :
A line is passing through points
,
= 1 , 4
,
= 3 , - 4
<u>Now, Equation of line in point-slope form is</u>
y -
= m × (x -
)
where m is the slope of line
∵ m = ![\dfrac{y_2 - y_1}{x_2 - x_1}](https://tex.z-dn.net/?f=%5Cdfrac%7By_2%20-%20y_1%7D%7Bx_2%20-%20x_1%7D)
i.e m = ![\dfrac{ ( - 4 ) - 4}{3 - 1}](https://tex.z-dn.net/?f=%5Cdfrac%7B%20%28%20-%204%20%29%20-%204%7D%7B3%20-%201%7D)
Or, m = ![\dfrac{ - 8}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%20-%208%7D%7B2%7D)
Or, m = - 4
So, The slope of line = m = - 4
∵, equation of line can be written as
y -
= m × (x -
)
<u>So, Putting the value of slope, m and points (
,
)</u>
i.e y - 4 = ( - 4 ) × ( x - 1 )
Or, y - 4 = ( - 4 ) × x + 4
Or, y - 4 = - 4 x + 4
Or, y = - 4 x + 4 + 4
∴ y = - 4 x + 8
So, The equation of line y = - 4 x + 8
Hence, The equation of line passing through points (1 , 4) and (3 , - 4) is y = - 4 x + 8 Answer