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4 years ago

Is a rectangle a polygon?

Mathematics

2 answers:

mihalych1998 [28]4 years ago

6 0

Yes because it has 4 sides

TiliK225 [7]4 years ago

5 0

Yes because it has 4 sides

Hope it heps

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Find the Integer of -3

Vesnalui [34]

Answer:

?????????????????????

3 0

3 years ago

appliances at a discountcity store on sale for 30% off the original price. eli has a couponfor an 18% discount on the sale price

VladimirAG [237]

Answer:

287

Step-by-step explanation:

8 0

4 years ago

The rate of depreciation dv / dt of a machine is inversely proportional to the square of t + 1, where v is the value of the mach

lukranit [14]

The solution for this problem is:
dV/dt = r/(t + 1)², V(0) = $500000, V(1) = $500000 - $200000 = $300000
∫dV = r∫ 1/(t + 1)² dt
V(t) = -r/(t + 1) + C
500000 = -r/(0 + 1) + C
400000 = -r/(1 + 1) + C
C = 300000, r = -100000
V(t) = 100000/(t + 1) + 300000
V(6) = 100000/(6+ 1) + 300000
V(6) = 14285.7143 + 300000

V(6) = $314285.71

6 0

3 years ago

Use a surface integral to find the general formula for the surface area of a cone with height latex: h and base radius latex: a(

BlackZzzverrR [31]

We can parameterize this part of a cone by

$\mathbf s(u,v)=\left\langle u\cos v,u\sin v,\dfrac hau\right\rangle$

with $0\le u\le a$ and $0\le v\le2\pi$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=\sqrt{1+\dfrac{h^2}{a^2}}u\,\mathrm du\,\mathrm dv$

The area of this surface (call it $\mathcal S$ ) is then

$\displaystyle\iint_{\mathcal S}\mathrm dS=\sqrt{1+\frac{h^2}{a^2}}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=a}u\,\mathrm du\,\mathrm dv=a^2\sqrt{1+\frac{h^2}{a^2}}\pi=a\sqrt{a^2+h^2}\pi$

6 0

3 years ago

Someone please help me

lina2011 [118]

Answer:

$\displaystyle \boxed{\frac{60}{61}} = cos\:θ_1$

Step-by-step explanation:

$\displaystyle arcsin\: \frac{11}{61} ≈ 0,1813197744 \\ \\ cos\:0,1813197744 ≈ \frac{60}{61}$

Since this answer is in Quadrant I, this would be a positive-positive answer, which in this case, will remain a positive.

Extended Information on Quadrants

$\displaystyle Positive-Negative → Quadrant\:IIII \\ Negative-Negative → Quadrant\:III \\ Negative-Positive → Quadrant\:II \\ Positive-Positive → Quadrant\:I \\ \\$

Extended Information on Trigonometric Ratio Values

$\displaystyle y-values → sin\:θ \\ x-values → cos\:θ$

I am joyous to assist you anytime.

5 0

4 years ago