It's a conditional probability
P( getting a given number AND getting again the same number)
P(of getting any number) =1/6
P(of getting once again the same number) 1/6 x 1/6 = 1/36
Segment DF is 1/2 the length of Segment DE. Since the entire segment is DE and it's midpoint is at F, the segment would be broken into 2 equal segments in one. Segment DF and FE. Segment DF is congruent to Segment FE.
Im notr sure but if we take the chances that the 4 sum has to be either (1.3) (3.1) (2.2) (2.2) that means its chance is 4/36 for each roll which is also 1/9 ,, we can multiply 1/9 times the roll times ( 252 ) we get =28
Is it possible it’s (-2,2)
The answer is b because each x value has one y value.
