Answer:
4^8
Step-by-step explanation:
If the second 4 is an exponent, as in (4^2)^4, then multiply the exponents.
(4^2)^4 = 4^(2 * 4) = 4^8
Answer:
no the solution would be (-2, -8)
Step-by-step explanation:
i graphed both of the equations and found the solution <33
200, 100, 200, and 100. if you mean HUNDRETH then they are all already to the nearest hundredth