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3 years ago

B. The number of cats your teammates have as pets: 0, 1, 3,2

Mathematics

1 answer:

algol [13]3 years ago

7 0

Ok so 1.2 is the answer you get if you divide them

and you can also say one because its counting by ones

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A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

8 0

3 years ago

You are paid $8.90 an hour for a 35-hour work week. You would like to work 5 hours a week overtime to earn extra money. How much

jeyben [28]

Answer:

$66.75 is what you'll make from over time.(this does not include the pay from the 35 hours this is only the over time)

Step-by-step explanation:

If you were to work (WITH OUT OVERTIME) you would have $311.50

If you were to work (WITH OVERTIME INCLUDED) you would get $378.25

5 0

3 years ago

Desribe how to use a tens fact to find the difference for 15-8

Fittoniya [83]

Answer/explanation :

Step-by-step

subtract 15-8 you have 7 then take

10- ur answer is 7

10-7= 3

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3 years ago

Samanth drew this pictogram

Elena-2011 [213]

Answer:

la verdad noce no me acuerdo

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2 years ago

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Someone pls help me with this question it’s due tomorrow helpppppp

scZoUnD [109]

Answer:

pretty easy

u calculate using the law of....

then add and subtract in the way of ..

6 0

3 years ago