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Hunter-Best [27]
2 years ago
5

You are riding the bus to school and you realize it is taking longer because of all the stops you are making. The time it takes

to get to school, measured in minutes, is modeled using the function g(x) = x4 − 3x2 + 4x − 5, where x is the number of stops the bus makes. If the bus makes 2 stops after you board, how long does it take you to get to school?
Mathematics
2 answers:
Sedaia [141]2 years ago
8 0

Answer:

7 minutes

Step-by-step explanation:

If x represents the number of stops, and there are 2 stops after you board, solving g(2) will give you the time it takes to get to school allowing time for x = 2 stops:

g(2)=(2)^4-3(2)^2+4(2)-5

This gives you, in minutes, that

g(2) = 7

nikitadnepr [17]2 years ago
6 0

Answer:

7 minutes

Step-by-step explanation:

  • start with formula

g(x) = x^4 - 3x^2 + 4x - 5

  • substitute x with number of stops (2)

g(2) = 2^4 - 3(2^2) + 4(2) - 5

  • simplify using p.e.m.d.a.s: start with exponents

g(2) = 16 - 3(4) + 4(2) - 5

  • multiply

g(2) = 16 - 12 + 8 - 5

  • subtract/add

16 - 12 = 4

4 + 8 = 12

12 - 5 = <u>7</u>

<u></u>

<u>input: 2</u>

<u>output: 7</u>

<u>ordered pair: (2,7)</u>

<u></u>

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Alla [95]

Answer:

First one is 41

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Step-by-step explanation:

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3 years ago
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fenix001 [56]

Answer:

I would say A

Step-by-step explanation:

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3 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

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x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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Answer:

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m_a_m_a [10]

Answer:

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Step-by-step explanation:

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