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kotegsom [21]
3 years ago
12

Which associations best describe the scatter plot? Select each correct answer. (A) linear association, (B) positive association,

(C) negative association, (D) nonlinear association

Mathematics
2 answers:
Fantom [35]3 years ago
7 0
Its C , a negative association because it is going from the top left to the bottom right which is knows as a negative association/negative correlation , hope this helps
Alecsey [184]3 years ago
7 0

The correct answer is (C) Negative association

Explanation:

A scatter plot is a type of graphic used to depict the relationship between two variables or factors using points in a vertical and horizontal axis. In this context, negative association or correlation occurs when the two variables do not increase or decrease together but one increases and the other decreases or vice-versa. This occurs in the scatter plot presented because the number of individuals infected (y-axis) decreases over time (x-axis). This means the first variable decreases while the second variable increases and therefore there is a negative association.

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Ten less than the prouduct of six and a number is 32. which equation would help you find the number
OlgaM077 [116]

Answer:

6x-10 =32

Step-by-step explanation:

Let the number be x

the product of 6 and a number

6x

ten less than

6x-10

That is equal to 32

6x-10 =32

3 0
3 years ago
Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1
IceJOKER [234]

Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

<u>Step-by-step explanation:</u>

Here we have , cosxtanx - 2 cos^2 x=-1. Let's solve :

⇒  cosxtanx - 2 cos^2 x=-1

⇒  cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1

⇒  sinx = 2 cos^2 x-1

⇒  sinx = 2 (1-sin^2x)-1

⇒  sinx = 1-2sin^2x

⇒  2sin^2x+sinx-1=0

By quadratic formula :

⇒ sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}

⇒ sinx = \frac{-1 \pm3}{4}

⇒ sinx = \frac{1}{2} , sinx =-1

⇒ sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}

⇒ x=\frac{\pi}{6} , x=\frac{3\pi}{2}

But at x=\frac{3\pi}{2} we have equation undefined as cos\frac{3\pi}{2}=0 . Hence only solution is :

⇒ x=\frac{\pi}{6}

Since , sin(\pi -x)=sinx

⇒ x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}

Now , General Solution is given by :

⇒ x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6}

Therefore , Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

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Answer:

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Step-by-step explanation:

27a + 1/3 * b = 4

Subtract the term with b from both sides.

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Divide both sides by 27.

a = 4/27 - 1/81 * b

a = 4/27 - b/81

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